What is area f(x)=x,g(x)=sqrt(x),[0,2] ?

The answer to area f(x)=x,g(x)=sqrt(x),[0,2] is (7-4sqrt(2))/3

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area f(x)=x,g(x)=sqrt(x),[0,2]

area

f (x) = x, g (x) = x, [0, 2]

\frac{7 - 4 2}{3}

Decimal Notation

0.44771 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x - x d x

Solve

\int_{0}^{2} x - x d x : \frac{7 - 4 2}{3}

The area is:

= \frac{7 - 4 2}{3}

\int_{2}^{25} sin (2 x) d x

\frac{\partial}{\partial x} (d x)

\int (6 x + 8) d x

\int \frac{1}{( 1 - x ^{2} )} d x

10 y^{^{''}} + 80 y^{^{'}} + 200 y = 0

What is area f(x)=x,g(x)=sqrt(x),[0,2] ?
The answer to area f(x)=x,g(x)=sqrt(x),[0,2] is (7-4sqrt(2))/3