What is the d/(d{r)}(6((6{r}-1)*k+{r})-1) ?

The d/(d{r)}(6((6{r}-1)*k+{r})-1) is 6(6k+1)

What is the first d/(d{r)}(6((6{r}-1)*k+{r})-1) ?

The first d/(d{r)}(6((6{r}-1)*k+{r})-1) is 6(6k+1)

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\frac{d}{d r} (6 ((6 r - 1) \cdot k + r) - 1)

6 (6 k + 1)

Solution steps

\frac{d}{d r} (6 ((6 r - 1) k + r) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (6 ((6 r - 1) k + r)) - \frac{d}{d r} (1)

\frac{d}{d r} (6 ((6 r - 1) k + r)) = 6 (6 k + 1)

\frac{d}{d r} (1) = 0

= 6 (6 k + 1) - 0

Simplify

= 6 (6 k + 1)

\frac{\partial}{\partial x} (ln (\frac{x}{x + y}))

n = 1 \sum \infty \frac{1}{( n + 2 ) ^{2}}

y = \frac{3}{16 - x}, at x = 0

\int x e^{- x (y + 1)} d x

\int \frac{( 2 x - 1 ) ^{2}}{2 x} d x

What is the d/(d{r)}(6((6{r}-1)*k+{r})-1) ?
The d/(d{r)}(6((6{r}-1)*k+{r})-1) is 6(6k+1)
What is the first d/(d{r)}(6((6{r}-1)*k+{r})-1) ?
The first d/(d{r)}(6((6{r}-1)*k+{r})-1) is 6(6k+1)