What is (\partial)/(\partial y)(2x^3y^2) ?

The answer to (\partial)/(\partial y)(2x^3y^2) is 4x^3y

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(\partial)/(\partial y)(2x^3y^2)

\frac{\partial}{\partial y} (2 x^{3} y^{2})

4 x^{3} y

Solution steps

\frac{\partial}{\partial y} (2 x^{3} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{3} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{3} \cdot 2 y^{2 - 1}

Simplify

= 4 x^{3} y

\int 4 x ln (2 x) d x

f (x) = x^{2} - 5 x + 5, at x = a

\int \frac{- x}{x - 1} d x

\int sin^{3} (θ) cos^{4} (θ) d θ

\int \frac{4}{x ln ^{3} ( x )} d x

What is (\partial)/(\partial y)(2x^3y^2) ?
The answer to (\partial)/(\partial y)(2x^3y^2) is 4x^3y