What is the derivative of 6sqrt(x)sin(x) ?

The derivative of 6sqrt(x)sin(x) is 6((sin(x))/(2sqrt(x))+sqrt(x)cos(x))

What is the first derivative of 6sqrt(x)sin(x) ?

The first derivative of 6sqrt(x)sin(x) is 6((sin(x))/(2sqrt(x))+sqrt(x)cos(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

6 x sin (x)

6 (\frac{sin ( x )}{2 x} + x cos (x))

Solution steps

\frac{d}{d x} (6 x sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x sin (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (x)

= 6 (\frac{d}{d x} (x) sin (x) + \frac{d}{d x} (sin (x)) x)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (sin (x)) = cos (x)

= 6 (\frac{1}{2 x} sin (x) + cos (x) x)

\frac{1}{2 x} sin (x) = \frac{sin ( x )}{2 x}

= 6 (\frac{sin ( x )}{2 x} + x cos (x))

\frac{\partial}{\partial y} (x^{\frac{x}{y}} cos (\frac{x}{y}))

((4 - x^{\frac{2}{3}})^{\frac{3}{2}})^{^{'}}

f (x) = \frac{1 + 2 x}{3 + x}

f (x) = (x - 1) e^{x^{2} - 4}

\frac{d y}{d x}, x y - 4 x = 5

What is the derivative of 6sqrt(x)sin(x) ?
The derivative of 6sqrt(x)sin(x) is 6((sin(x))/(2sqrt(x))+sqrt(x)cos(x))
What is the first derivative of 6sqrt(x)sin(x) ?
The first derivative of 6sqrt(x)sin(x) is 6((sin(x))/(2sqrt(x))+sqrt(x)cos(x))