What is laplacetransform 2(t-2)^2 ?

The answer to laplacetransform 2(t-2)^2 is 2(2/(s^3)-4/(s^2)+4/s)

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laplacetransform 2(t-2)^2

laplace transform

2 (t - 2)^{2}

2 (\frac{2}{s ^{3}} - \frac{4}{s ^{2}} + \frac{4}{s})

Solution steps

L {2 (t - 2)^{2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {(t - 2)^{2}}

L {(t - 2)^{2}} : \frac{2}{s ^{3}} - \frac{4}{s ^{2}} + \frac{4}{s}

= 2 (\frac{2}{s ^{3}} - \frac{4}{s ^{2}} + \frac{4}{s})

\frac{d y}{d x} = \frac{3 x + 1}{4 y}

\int_{0}^{1} \frac{5 x ^{4}}{1 + x ^{5}} d x

\int (6 x - 2)^{- 4} d x

\int \frac{2 r}{( 1 - r ) ^{7}} d r

y = x^{2}, y = 2 - x

What is laplacetransform 2(t-2)^2 ?
The answer to laplacetransform 2(t-2)^2 is 2(2/(s^3)-4/(s^2)+4/s)