What is the derivative of f(x)=-3x^2+4x+20 ?

The derivative of f(x)=-3x^2+4x+20 is -6x+4

What is the first derivative of f(x)=-3x^2+4x+20 ?

The first derivative of f(x)=-3x^2+4x+20 is -6x+4

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derivative of

f (x) = - 3 x^{2} + 4 x + 20

- 6 x + 4

Solution steps

\frac{d}{d x} (- 3 x^{2} + 4 x + 20)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (20)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (20) = 0

= - 6 x + 4 + 0

Simplify

= - 6 x + 4

x \to 3 lim (\frac{x - 5}{x + 3})

2 sin (t)

\int arctan (2 x) d x

\frac{\partial}{\partial x} (10 (11 x - 3 y + 12)^{5})

What is the derivative of f(x)=-3x^2+4x+20 ?
The derivative of f(x)=-3x^2+4x+20 is -6x+4
What is the first derivative of f(x)=-3x^2+4x+20 ?
The first derivative of f(x)=-3x^2+4x+20 is -6x+4