What is area f(x)=2x^3+3x^2+5x,-4,3 ?

The answer to area f(x)=2x^3+3x^2+5x,-4,3 is 194

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area f(x)=2x^3+3x^2+5x,-4,3

area

f (x) = 2 x^{3} + 3 x^{2} + 5 x, - 4, 3

194

Solution steps

Apply the area formula:

\int_{- 4}^{3} 2 x^{3} + 3 x^{2} + 5 x d x

Solve

\int_{- 4}^{3} 2 x^{3} + 3 x^{2} + 5 x d x : 194

The area is:

= 194

\frac{\partial}{\partial x} (e^{3 x} sin (3 y))

\frac{d}{d x} (c_{1} e^{x} + c_{2} x e^{x})

n = 0 \sum \infty \frac{1}{1 0 ^{n}}

y^{^{'}} + 7 y = t + e^{- 2 t}

x \to 0 + lim (x^{3} + 3 x + 2)

What is area f(x)=2x^3+3x^2+5x,-4,3 ?
The answer to area f(x)=2x^3+3x^2+5x,-4,3 is 194