What is the tangent of y=x^2-2x+3,(2,3) ?

The tangent of y=x^2-2x+3,(2,3) is y=2x-1

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tangent of y=x^2-2x+3,(2,3)

tangent of

y = x^{2} - 2 x + 3, (2, 3)

y = 2 x - 1

Solution steps

Find the slope of

y = x^{2} - 2 x + 3 : \frac{d y}{d x} = 2 x - 2

Compute the slope of

y = x^{2} - 2 x + 3

(2, 3) : m = 2

Find the line with slope m=

2

and passing through

(2, 3) : y = 2 x - 1

y = 2 x - 1

\frac{\partial}{\partial x} (7 x)

\frac{( x ^{2} + 1 ) d y}{d x} + 7 x (y - 1) = 0

\int x \cdot (3 x + x) d x

\frac{\partial}{\partial x} (e^{4 x})

t^{2} sin (5 t)

What is the tangent of y=x^2-2x+3,(2,3) ?
The tangent of y=x^2-2x+3,(2,3) is y=2x-1