What is the tangent of f(x)=3x-2x^2,(-3,-27) ?

The tangent of f(x)=3x-2x^2,(-3,-27) is y=15x+18

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tangent of f(x)=3x-2x^2,(-3,-27)

tangent of

f (x) = 3 x - 2 x^{2}, (- 3, - 27)

y = 15 x + 18

Solution steps

Find the slope of

f (x) = 3 x - 2 x^{2} : \frac{df ( x )}{d x} = 3 - 4 x

Compute the slope of

f (x) = 3 x - 2 x^{2}

(- 3, - 27) : m = 15

Find the line with slope m=

15

and passing through

(- 3, - 27) : y = 15 x + 18

y = 15 x + 18

x \to 0 lim (π^{2})

\frac{d ^{2}}{d x ^{2}} (\frac{( x - 5 ) ( x ^{2} + 5 x + 25 )}{x ^{3}})

\int (1 + tan (x))^{3} sec^{2} (x) d x

\int - \frac{1}{2} cos (2 t) d t

\int 3 sec (2 x) tan (2 x) d x

What is the tangent of f(x)=3x-2x^2,(-3,-27) ?
The tangent of f(x)=3x-2x^2,(-3,-27) is y=15x+18