What is (d^2)/(dx^2)(-cos(x)ln(sec(x)+tan(x))) ?

The answer to (d^2)/(dx^2)(-cos(x)ln(sec(x)+tan(x))) is cos(x)ln(sec(x)+tan(x))+tan(x)

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(d^2)/(dx^2)(-cos(x)ln(sec(x)+tan(x)))

\frac{d ^{2}}{d x ^{2}} (- cos (x) ln (sec (x) + tan (x)))

cos (x) ln (sec (x) + tan (x)) + tan (x)

Solution steps

\frac{d ^{2}}{d x ^{2}} (- cos (x) ln (sec (x) + tan (x)))

\frac{d}{d x} (- cos (x) ln (sec (x) + tan (x))) = - (1 - ln (sec (x) + tan (x)) sin (x))

= \frac{d}{d x} (- (1 - ln (sec (x) + tan (x)) sin (x)))

\frac{d}{d x} (- (1 - ln (sec (x) + tan (x)) sin (x))) = cos (x) ln (sec (x) + tan (x)) + tan (x)

= cos (x) ln (sec (x) + tan (x)) + tan (x)

\int \frac{10}{x ^{5}} d x

t y^{^{'}} + 2 y = \frac{2}{1 + t ^{2}}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{x} sin (2 x)

\frac{\partial}{\partial x} (arctan (2 x y))

What is (d^2)/(dx^2)(-cos(x)ln(sec(x)+tan(x))) ?
The answer to (d^2)/(dx^2)(-cos(x)ln(sec(x)+tan(x))) is cos(x)ln(sec(x)+tan(x))+tan(x)