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Popular >

area y=x^2,x+y=2

Solution

area

y = x^{2}, x + y = 2

Solution

\frac{9}{2}

+1

Decimal Notation

4.5

Solution steps

Isolate

y

for

x + y = 2 : y = 2 - x

Apply the area formula:

\int_{- 2}^{1} x^{2} - (2 - x) d x

Solve

\int_{- 2}^{1} x^{2} - (2 - x) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Popular Examples

y^'+1/2*y= 3/2*t

y^{^{'}} + \frac{1}{2} \cdot y = \frac{3}{2} \cdot t

derivative of B(x-2)^2x^2 derivative of

B (x - 2)^{2} x^{2}

integral of (2x)/(x+5)

\int \frac{2 x}{x + 5} d x

integral from 0 to 1 of 7x

\int_{0}^{1} 7 x d x

integral of 2x^3e^{3x}

\int 2 x^{3} e^{3 x} d x

Frequently Asked Questions (FAQ)

What is area y=x^2,x+y=2 ?
The answer to area y=x^2,x+y=2 is 9/2