What is the integral of (x^2-x-1)^3(2x-1) ?

The integral of (x^2-x-1)^3(2x-1) is ((x^2-x-1)^4)/4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2-x-1)^3(2x-1)

\int (x^{2} - x - 1)^{3} (2 x - 1) d x

\frac{( x ^{2} - x - 1 ) ^{4}}{4} + C

Solution steps

\int (x^{2} - x - 1)^{3} (2 x - 1) d x

Apply u-substitution

: \int u^{3} d u

= \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= \frac{u ^{4}}{4}

Substitute back

u = x^{2} - x - 1

= \frac{( x ^{2} - x - 1 ) ^{4}}{4}

Add a constant to the solution

= \frac{( x ^{2} - x - 1 ) ^{4}}{4} + C

\frac{d}{d x} (\frac{e ^{2 x}}{x})

f (x) = 4 x + \frac{6}{x}, (5, 21.2)

\int 2 x (x^{2} + 14)^{5} d x

\int \frac{sin ^{4} ( x )}{x} d x

\frac{d}{d s} (\frac{4}{s ^{2} + 16})

What is the integral of (x^2-x-1)^3(2x-1) ?
The integral of (x^2-x-1)^3(2x-1) is ((x^2-x-1)^4)/4+C