What is the derivative of f(x)=(4pi^2)/(6-x) ?

The derivative of f(x)=(4pi^2)/(6-x) is (4pi^2)/((6-x)^2)

What is the first derivative of f(x)=(4pi^2)/(6-x) ?

The first derivative of f(x)=(4pi^2)/(6-x) is (4pi^2)/((6-x)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{4 π ^{2}}{6 - x}

\frac{4 π ^{2}}{( 6 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 π ^{2}}{6 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 π^{2} \frac{d}{d x} (\frac{1}{6 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 π^{2} \frac{d}{d x} ((6 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 6 - x ) ^{2}} \frac{d}{d x} (6 - x)

= - \frac{1}{( 6 - x ) ^{2}} \frac{d}{d x} (6 - x)

\frac{d}{d x} (6 - x) = - 1

= 4 π^{2} (- \frac{1}{( 6 - x ) ^{2}} (- 1))

Simplify

4 π^{2} (- \frac{1}{( 6 - x ) ^{2}} (- 1)) : \frac{4 π ^{2}}{( 6 - x ) ^{2}}

= \frac{4 π ^{2}}{( 6 - x ) ^{2}}

\frac{d}{d x} ((x + x^{- 1})^{3})

\frac{\partial}{\partial x} (e^{8 x + 2 y})

\frac{d}{d x} (\frac{4 x}{( 2 x + 1 ) ^{2}})

\int \frac{( x ^{2} + 1 )}{x ^{3} + 3 x} d x

\frac{\partial}{\partial x} (ln (x^{6} + y^{4}))

What is the derivative of f(x)=(4pi^2)/(6-x) ?
The derivative of f(x)=(4pi^2)/(6-x) is (4pi^2)/((6-x)^2)
What is the first derivative of f(x)=(4pi^2)/(6-x) ?
The first derivative of f(x)=(4pi^2)/(6-x) is (4pi^2)/((6-x)^2)