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Popular >

midpoint (-8,-9),(-5,1)

Solution

midpoint

(- 8, - 9), (- 5, 1)

Solution

(- \frac{13}{2}, - 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 8, - 9), (x_{2}, y_{2}) = (- 5, 1)

= (\frac{- 5 - 8}{2}, \frac{1 - 9}{2})

Refine

= (- \frac{13}{2}, - 4)

Popular Examples

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extreme f(x)=xe^{1/x}extreme points

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inverse of f(x)=(9x-1)/(2x+4)inverse

f (x) = \frac{9 x - 1}{2 x + 4}

slope ofintercept 2x-9y-4=0 slope intercept

2 x - 9 y - 4 = 0

domain of f(x)=ln(((|x|-1))/(x^2-2))domain

f (x) = ln (\frac{( ∣ x ∣ - 1 )}{x ^{2} - 2})

Frequently Asked Questions (FAQ)

What is the midpoint (-8,-9),(-5,1) ?
The midpoint (-8,-9),(-5,1) is (-13/2 ,-4)