What is the critical f(x)= x/(x^2+16x+60) ?

The critical f(x)= x/(x^2+16x+60) is x=-2sqrt(15),x=2sqrt(15)

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critical f(x)= x/(x^2+16x+60)

critical points

f (x) = \frac{x}{x ^{2} + 16 x + 60}

x = - 215, x = 215

Solution steps

\frac{x}{x ^{2} + 16 x + 60}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 215, x = 215, x = - 10, x = - 6

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 16 x + 60} : x < - 10 or - 10 < x < - 6 or x > - 6

\frac{x}{x ^{2} + 16 x + 60}

is not defined at

x = - 10, x = - 6

, therefore:

x = - 215, x = 215

f (x) = \frac{1}{x - 1}

\frac{6 x - 1}{2 x + 5}

f (x) = \frac{9}{x}

g (x) = \frac{x ^{2}}{x - 4}

f (x) = \frac{1}{2} x + 6

What is the critical f(x)= x/(x^2+16x+60) ?
The critical f(x)= x/(x^2+16x+60) is x=-2sqrt(15),x=2sqrt(15)