What are the solutions to the equation (x^2+5)(8-x)=0 ?

The solutions to the equation (x^2+5)(8-x)=0 are x=sqrt(5)i,x=-sqrt(5)i,x=8

Find the zeros of (x^2+5)(8-x)=0

The zeros of (x^2+5)(8-x)=0 are x=sqrt(5)i,x=-sqrt(5)i,x=8

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(x^{2} + 5) (8 - x) = 0

x = 5 i, x = - 5 i, x = 8

Solution steps

(x^{2} + 5) (8 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 5 = 0 or 8 - x = 0

Solve

x^{2} + 5 = 0 : x = 5 i, x = - 5 i

Solve

8 - x = 0 : x = 8

The solutions are

x = 5 i, x = - 5 i, x = 8

f (x) = \frac{2 x + 3}{x ^{3}}

f (x) = (\frac{1}{2})^{x} + 3

f (x) = (x - 3)^{2} - 1

2 (\frac{1}{3})^{x}

3 x + 2 y = - 7, (1, 1)

What are the solutions to the equation (x^2+5)(8-x)=0 ?
The solutions to the equation (x^2+5)(8-x)=0 are x=sqrt(5)i,x=-sqrt(5)i,x=8
Find the zeros of (x^2+5)(8-x)=0
The zeros of (x^2+5)(8-x)=0 are x=sqrt(5)i,x=-sqrt(5)i,x=8