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Popular >

y=x^2+2x+1

Solution

y = x^{2} + 2 x + 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 0

X Intercepts : (- 1, 0), Y Intercepts : (0, 1)

Vertex : Minimum (- 1, 0)

Inverse : - 1 + x, - x - 1

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [0, \infty)

Solution steps

Domain of

x^{2} + 2 x + 1 : - \infty < x < \infty

Range of

x^{2} + 2 x + 1 : f (x) \geq 0

Axis interception points of

x^{2} + 2 x + 1 :

X Intercepts

: (- 1, 0),

Y Intercepts

: (0, 1)

Vertex of

x^{2} + 2 x + 1 :

Minimum

(- 1, 0)

Inverse of

x^{2} + 2 x + 1 : - 1 + x, - x - 1

Popular Examples

extreme f(x)=x^4-7x^3 extreme points

f (x) = x^{4} - 7 x^{3}

asymptotes of f(x)=(2/5)^x asymptotes

f (x) = (\frac{2}{5})^{x}

intercepts of y=-3/4 x-2 intercepts

y = - \frac{3}{4} x - 2

range of 1+8x-2x^3 range

1 + 8 x - 2 x^{3}

domain of (sqrt(x-2))^2+3 domain

(x - 2)^{2} + 3

Frequently Asked Questions (FAQ)

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