What is the domain of f(x)= 1/(x^2-2x) ?

The domain of f(x)= 1/(x^2-2x) is x 2

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domain of f(x)= 1/(x^2-2x)

domain

f (x) = \frac{1}{x ^{2} - 2 x}

x < 0 or 0 < x < 2 or x > 2

Interval Notation

(- \infty, 0) \cup (0, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = 0

The function domain

x < 0 or 0 < x < 2 or x > 2

f (x) = 4 - \frac{2}{t ^{2}}

f (x) = 3 x^{2} + 2 x - 3

f (x) = \frac{3 x}{2}

f (x) = - x^{2} + 3

f (x) = 2 tan (4 x - 32)

What is the domain of f(x)= 1/(x^2-2x) ?
The domain of f(x)= 1/(x^2-2x) is x<0\lor 0<x<2\lor x>2