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Popular >

midpoint (5,9),(10,-1)

Solution

midpoint

(5, 9), (10, - 1)

Solution

(\frac{15}{2}, 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (5, 9), (x_{2}, y_{2}) = (10, - 1)

= (\frac{10 + 5}{2}, \frac{- 1 + 9}{2})

Refine

= (\frac{15}{2}, 4)

Popular Examples

extreme f(x)=x^6-3x^5 extreme points

f (x) = x^{6} - 3 x^{5}

extreme f(x)=x^2-3x+1 extreme points

f (x) = x^{2} - 3 x + 1

midpoint (5,5),(-10,-2)midpoint

(5, 5), (- 10, - 2)

range of f(x)=sqrt(1-x^2)range

f (x) = 1 - x^{2}

inverse of y=x^2+1 inverse

y = x^{2} + 1

Frequently Asked Questions (FAQ)

What is the midpoint (5,9),(10,-1) ?
The midpoint (5,9),(10,-1) is (15/2 ,4)