What is the domain of f(x)=(x-5)/(x^2+1) ?

The domain of f(x)=(x-5)/(x^2+1) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-5)/(x^2+1)

domain

f (x) = \frac{x - 5}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{2 x}{x ^{2} - 1}

f (x) = \frac{- 5 - x}{5 + x}

- 2 cos (3 x)

f (x) = - \frac{1}{4 x}

f (x) = x + \frac{1}{x ^{2}}

What is the domain of f(x)=(x-5)/(x^2+1) ?
The domain of f(x)=(x-5)/(x^2+1) is -infinity <x<infinity