What is the inflection f(x)=4x^3-6x^2+6x-9 ?

The inflection f(x)=4x^3-6x^2+6x-9 is (1/2 ,-7)

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inflection f(x)=4x^3-6x^2+6x-9

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 6 x - 9

(\frac{1}{2}, - 7)

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 6 x - 9 : - 7

(\frac{1}{2}, - 7)

y = 5

\frac{ln ( x ) + 1}{ln ( x ) - 1}

f (x) = (- x)^{\frac{1}{2}}

(- 7, - 7), (- 5, 5)

f (x) = x^{2} + 3 x

What is the inflection f(x)=4x^3-6x^2+6x-9 ?
The inflection f(x)=4x^3-6x^2+6x-9 is (1/2 ,-7)