What is -4<= (3x+11)/7 <3 ?

The solution to -4<= (3x+11)/7 <3 is -13<= x< 10/3

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-4<= (3x+11)/7 <3

- 4 \leq \frac{3 x + 11}{7} < 3

- 13 \leq x < \frac{10}{3}

Interval Notation

[- 13, \frac{10}{3})

Decimal Notation

- 13 \leq x < 3.33333 \dots

Solution steps

- 4 \leq \frac{3 x + 11}{7} < 3

a \leq u < b

then

a \leq u and u < b

- 4 \leq \frac{3 x + 11}{7} and \frac{3 x + 11}{7} < 3

- 4 \leq \frac{3 x + 11}{7} : x \geq - 13

\frac{3 x + 11}{7} < 3 : x < \frac{10}{3}

Combine the intervals

x \geq - 13 and x < \frac{10}{3}

Merge Overlapping Intervals

- 13 \leq x < \frac{10}{3}

\frac{x + 4}{3} - \frac{x}{7} = \frac{x + 7}{5}

x (1 - b) - y (1 - b)

x^{2} - 15 x + 36

- 1.5 (t - 2) = - 10.5

(\frac{81}{169})^{\frac{1}{2}}