(2k-9)(2k-1)<0

Lösung

(2 k - 9) (2 k - 1) < 0

\frac{1}{2} < k < \frac{9}{2}

Intervall-Notation

(\frac{1}{2}, \frac{9}{2})

Dezimale

0.5 < k < 4.5

Schritte zur Lösung

(2 k - 9) (2 k - 1) < 0

Identifiziere die Intervalle

\frac{1}{2} < k < \frac{9}{2}

f a c t or 8 x^{2} - 4 x

2 x + 4 < 5 x + 3

5 a^{2} - 7 = 4

- 3 + 4 x = 25

10 < r