What are the solutions to the equation (x+2sqrt(10))(x-sqrt(40))=sqrt(36) ?

The solutions to the equation (x+2sqrt(10))(x-sqrt(40))=sqrt(36) are x=sqrt(46),x=-sqrt(46)

Find the zeros of (x+2sqrt(10))(x-sqrt(40))=sqrt(36)

The zeros of (x+2sqrt(10))(x-sqrt(40))=sqrt(36) are x=sqrt(46),x=-sqrt(46)

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(x + 210) (x - 40) = 36

x = 46, x = - 46

Decimal Notation

x = 6.78232 \dots, x = - 6.78232 \dots

Solution steps

(x + 210) (x - 40) = 36

Expand

(x + 210) (x - 40) : x^{2} - 40

x^{2} - 40 = 6

Move

6

to the left side

x^{2} - 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 46 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 46) = 246

x_{1, 2} = \frac{- 0 \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2 46}{2 \cdot 1}, x_{2} = \frac{- 0 - 2 46}{2 \cdot 1}

x = \frac{- 0 + 2 46}{2 \cdot 1} : 46

x = \frac{- 0 - 2 46}{2 \cdot 1} : - 46

The solutions to the quadratic equation are:

x = 46, x = - 46

2 x^{2} - 9 x + 11 = 4

15 \cdot \frac{π}{180}

lo g_{\frac{1}{3}} (9) = x

n^{2} + n - 30

2 x^{2} + 2 x y - 5 x - 5 y

What are the solutions to the equation (x+2sqrt(10))(x-sqrt(40))=sqrt(36) ?
The solutions to the equation (x+2sqrt(10))(x-sqrt(40))=sqrt(36) are x=sqrt(46),x=-sqrt(46)
Find the zeros of (x+2sqrt(10))(x-sqrt(40))=sqrt(36)
The zeros of (x+2sqrt(10))(x-sqrt(40))=sqrt(36) are x=sqrt(46),x=-sqrt(46)