What are the solutions to the equation x^2-8x+1=0 ?

The solutions to the equation x^2-8x+1=0 are x=4+sqrt(15),x=4-sqrt(15)

Find the zeros of x^2-8x+1=0

The zeros of x^2-8x+1=0 are x=4+sqrt(15),x=4-sqrt(15)

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x^{2} - 8 x + 1 = 0

x = 4 + 15, x = 4 - 15

Decimal Notation

x = 7.87298 \dots, x = 0.12701 \dots

Solution steps

x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 1 = 215

x_{1, 2} = \frac{- ( - 8 ) \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 15}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 15}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 15}{2 \cdot 1} : 4 + 15

x = \frac{- ( - 8 ) - 2 15}{2 \cdot 1} : 4 - 15

The solutions to the quadratic equation are:

x = 4 + 15, x = 4 - 15

m^{2} - 1 = 0

4 (x - 5) - 5 (x - 4) = x + 4 - (x - 3)

(3 x + 2) (x - 1) - 13 = 2 x (2 - x)

2 x^{2} + 17 x + 30

\frac{60 m ^{- 3} m ^{2}}{- 15 n ^{- 1} n ^{5}}

What are the solutions to the equation x^2-8x+1=0 ?
The solutions to the equation x^2-8x+1=0 are x=4+sqrt(15),x=4-sqrt(15)
Find the zeros of x^2-8x+1=0
The zeros of x^2-8x+1=0 are x=4+sqrt(15),x=4-sqrt(15)