What are the solutions to the equation 3x^2+x-8=0 ?

The solutions to the equation 3x^2+x-8=0 are x=(-1+sqrt(97))/6 ,x=(-1-sqrt(97))/6

Find the zeros of 3x^2+x-8=0

The zeros of 3x^2+x-8=0 are x=(-1+sqrt(97))/6 ,x=(-1-sqrt(97))/6

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3 x^{2} + x - 8 = 0

x = \frac{- 1 + 97}{6}, x = \frac{- 1 - 97}{6}

Decimal Notation

x = 1.47480 \dots, x = - 1.80814 \dots

Solution steps

3 x^{2} + x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 8) = 97

x_{1, 2} = \frac{- 1 \pm 97}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 97}{2 \cdot 3}, x_{2} = \frac{- 1 - 97}{2 \cdot 3}

x = \frac{- 1 + 97}{2 \cdot 3} : \frac{- 1 + 97}{6}

x = \frac{- 1 - 97}{2 \cdot 3} : \frac{- 1 - 97}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 97}{6}, x = \frac{- 1 - 97}{6}

\frac{8 !}{6 !}

x^{2} + 7 x = 3 x

- \frac{3}{4} m + \frac{1}{2} m - \frac{1}{2} m = - \frac{7}{12}

8 (8 + x) = 7 + 19

4 x^{2} - 8 x + 3 = 0

What are the solutions to the equation 3x^2+x-8=0 ?
The solutions to the equation 3x^2+x-8=0 are x=(-1+sqrt(97))/6 ,x=(-1-sqrt(97))/6
Find the zeros of 3x^2+x-8=0
The zeros of 3x^2+x-8=0 are x=(-1+sqrt(97))/6 ,x=(-1-sqrt(97))/6