erweitern (x'y(x,z(x))z(x)+xy(x,z(x))z(x))(x+y(x,z))

Lösung

erweitern

(x^{^{'}} y (x, z (x)) z (x) + x y (x, z (x)) z (x)) (x + y (x, z))

(x) x z x^{'} y (, x (x) z) + (x) z x^{'} y (, x (x) z) y (, x z) + x (x) x zy (, x (x) z) + x (x) zy (, x (x) z) y (, x z)

Schritte zur Lösung

(x^{^{'}} y (x, z (x)) z (x) + x y (x, z (x)) z (x)) (x + y (x, z))

= ((x) z x^{^{^{'}}} y (, x (x) z) + x (x) zy (, x (x) z)) (x + y (, x z))

Wende Ausklammerungsregel an (VANI):

(a + b) (c + d) = a c + a d + b c + b d

a = x^{^{'}} y (x, z (x)) z (x), b = x y (x, z (x)) z (x), c = x, d = y (x, z)

= x^{^{^{'}}} y (x, z (x)) z (x) x + x^{^{^{'}}} y (x, z (x)) z (x) y (x, z) + x y (x, z (x)) z (x) x + x y (x, z (x)) z (x) y (x, z)

= (x) x z x^{^{^{'}}} y (, x (x) z) + (x) z x^{^{^{'}}} y (, x (x) z) y (, x z) + x (x) x zy (, x (x) z) + x (x) zy (, x (x) z) y (, x z)

e x p an d (x - 2) (x - 3) (x - 5)

e x p an d \frac{1}{( 1 + 2 x ) ^{2}}

e x p an d \frac{7}{( x + 2 ) ^{2}}

e x p an d (2 + 2 sin (θ))^{2}

e x p an d \frac{( - 9 + j ) ( - 9 - j )}{( 3 + j ) ( 5 - 4 j )}