4m^2-4m+1=0

解

4 m^{2} - 4 m + 1 = 0

m = \frac{1}{2}

十進法表記

m = 0.5

解答ステップ

4 m^{2} - 4 m + 1 = 0

解くとthe二次式

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

m_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

m = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

m = \frac{1}{2}

二次equationの解:

m = \frac{1}{2}