We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What are the solutions to the equation 2y^2+10=-7 ?
- The solutions to the equation 2y^2+10=-7 are y=sqrt(17/2)i,y=-sqrt(17/2)i
Find the zeros of 2y^2+10=-7
- The zeros of 2y^2+10=-7 are y=sqrt(17/2)i,y=-sqrt(17/2)i