What are the solutions to the equation x^2+9x-9=0 ?

The solutions to the equation x^2+9x-9=0 are x=(-9+3sqrt(13))/2 ,x=(-9-3sqrt(13))/2

Find the zeros of x^2+9x-9=0

The zeros of x^2+9x-9=0 are x=(-9+3sqrt(13))/2 ,x=(-9-3sqrt(13))/2

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x^{2} + 9 x - 9 = 0

x = \frac{- 9 + 3 13}{2}, x = \frac{- 9 - 3 13}{2}

Decimal Notation

x = 0.90832 \dots, x = - 9.90832 \dots

Solution steps

x^{2} + 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 9) = 313

x_{1, 2} = \frac{- 9 \pm 3 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 3 13}{2 \cdot 1}, x_{2} = \frac{- 9 - 3 13}{2 \cdot 1}

x = \frac{- 9 + 3 13}{2 \cdot 1} : \frac{- 9 + 3 13}{2}

x = \frac{- 9 - 3 13}{2 \cdot 1} : \frac{- 9 - 3 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 3 13}{2}, x = \frac{- 9 - 3 13}{2}

\frac{3}{4} + \frac{1}{3}

\frac{6}{5 - i}

x^{2} - 2 x - 3 > 0

n^{2} - 4 n + 3

- 3 (3 x - 8) = 3 x

What are the solutions to the equation x^2+9x-9=0 ?
The solutions to the equation x^2+9x-9=0 are x=(-9+3sqrt(13))/2 ,x=(-9-3sqrt(13))/2
Find the zeros of x^2+9x-9=0
The zeros of x^2+9x-9=0 are x=(-9+3sqrt(13))/2 ,x=(-9-3sqrt(13))/2