簡約 (sqrt(x)-i)^2

解

簡約

(x - i)^{2}

((x)^{2} - 1) - 2 x i

解答ステップ

(x - i)^{2}

完全平方式を適用する:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x - i)^{2} = (x)^{2} - 2 x i + i^{2}

= (x)^{2} - 2 x i + i^{2}

虚数の規則を適用する:

i^{2} = - 1

= (x)^{2} - 2 x i - 1

標準的な複素数形式で書き直す:

((x)^{2} - 1) - 2 x i

= ((x)^{2} - 1) - 2 x i

e x p an d \frac{9 ( - 189 π + 1620 )}{10}

e x p an d (sin (y) - y sin (x)) d x + (cos (x) + x cos (y) - y) d y

e x p an d \frac{10 x + 0.5}{( x ^{2} - 1.2 x + 0.2 ) ( x - 1 )}

e x p an d \frac{2 ( 2 x - 1 )}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

e x p an d \frac{x ^{3} + x ^{2} + 1}{x ( x - 1 ) ( x ^{2} + x + 1 ) ( x ^{2} + 1 ) ^{3}}