展开 (1/2-2p)^2

解答

展开

(\frac{1}{2} - 2 p)^{2}

\frac{1 - 8 p + 16 p ^{2}}{4}

求解步骤

(\frac{1}{2} - 2 p)^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{1}{2} - 2 p)^{2} = (\frac{1}{2})^{2} - 2 \cdot \frac{1}{2} \cdot 2 p + (2 p)^{2}

= (\frac{1}{2})^{2} - 2 \cdot \frac{1}{2} \cdot 2 p + (2 p)^{2}

化简

(\frac{1}{2})^{2} - 2 \cdot \frac{1}{2} \cdot 2 p + (2 p)^{2} : \frac{1 - 8 p + 16 p ^{2}}{4}

= \frac{1 - 8 p + 16 p ^{2}}{4}

e x p an d 1 - 2 x (1 - 2 x)

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