erweitern (log_{10}(3)[(x+y)^2])/([x^2+y^2])

Lösung

erweitern

\frac{lo g _{10} ( 3 ) [ ( x + y ) ^{2} ]}{[ x ^{2} + y ^{2} ]}

\frac{lo g _{10} ( 3 ) x ^{2} + 2 lo g _{10} ( 3 ) x y + lo g _{10} ( 3 ) y ^{2}}{x ^{2} + y ^{2}}

Schritte zur Lösung

\frac{lo g _{10} ( 3 ) ( ( x + y ) ^{2} )}{x ^{2} + y ^{2}}

Entferne die Klammern:

(a) = a

= \frac{lo g _{10} ( 3 ) ( x + y ) ^{2}}{x ^{2} + y ^{2}}

(x + y)^{2} = x^{2} + 2 x y + y^{2}

= \frac{lo g _{10} ( 3 ) ( x ^{2} + 2 x y + y ^{2} )}{x ^{2} + y ^{2}}

Multipliziere aus

lo g_{10} (3) (x^{2} + 2 x y + y^{2}) : lo g_{10} (3) x^{2} + 2 lo g_{10} (3) x y + lo g_{10} (3) y^{2}

= \frac{lo g _{10} ( 3 ) x ^{2} + 2 lo g _{10} ( 3 ) x y + lo g _{10} ( 3 ) y ^{2}}{x ^{2} + y ^{2}}

\frac{d}{d M} ((R) (M^{2} (\frac{c}{2} - \frac{M}{3})))

e x p an d \frac{( 3 s + 8 )}{( s + 3 ) ^{2}}

e x p an d \frac{4 x ^{2} - 14 x - 30}{x ( x - 3 )}

e x p an d (x - \frac{31}{2})^{2} + x

e x p an d (t^{\frac{1}{2}} + t^{\frac{1}{3}})^{3}