What are the solutions to the equation x^2-5/2 x+1=0 ?

The solutions to the equation x^2-5/2 x+1=0 are x=2,x= 1/2

Find the zeros of x^2-5/2 x+1=0

The zeros of x^2-5/2 x+1=0 are x=2,x= 1/2

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x^{2} - \frac{5}{2} x + 1 = 0

x = 2, x = \frac{1}{2}

Decimal Notation

x = 2, x = 0.5

Solution steps

x^{2} - \frac{5}{2} x + 1 = 0

Multiply both sides by

2

2 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 2}

x = \frac{- ( - 5 ) + 3}{2 \cdot 2} : 2

x = \frac{- ( - 5 ) - 3}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{2}

0.2 \cdot y \cdot (1 - (\frac{y}{5})) - 0.24 = 0

(2 i)^{3}

- 5 (z + 1) = - 2 z + 10

- 1 \leq x - 3 < 4

5 x \geq - 10

What are the solutions to the equation x^2-5/2 x+1=0 ?
The solutions to the equation x^2-5/2 x+1=0 are x=2,x= 1/2
Find the zeros of x^2-5/2 x+1=0
The zeros of x^2-5/2 x+1=0 are x=2,x= 1/2