erweitern ((3x^2+10y^4)^2)/(16)

Lösung

erweitern

\frac{( 3 x ^{2} + 10 y ^{4} ) ^{2}}{16}

\frac{9 x ^{4}}{16} + \frac{15 x ^{2} y ^{4}}{4} + \frac{25 y ^{8}}{4}

Schritte zur Lösung

\frac{( 3 x ^{2} + 10 y ^{4} ) ^{2}}{16}

(3 x^{2} + 10 y^{4})^{2} = 9 x^{4} + 60 x^{2} y^{4} + 100 y^{8}

= \frac{9 x ^{4} + 60 x ^{2} y ^{4} + 100 y ^{8}}{16}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{4} + 60 x ^{2} y ^{4} + 100 y ^{8}}{16} = \frac{9 x ^{4}}{16} + \frac{60 x ^{2} y ^{4}}{16} + \frac{100 y ^{8}}{16}

= \frac{9 x ^{4}}{16} + \frac{60 x ^{2} y ^{4}}{16} + \frac{100 y ^{8}}{16}

Streiche

\frac{60 x ^{2} y ^{4}}{16} : \frac{15 x ^{2} y ^{4}}{4}

= \frac{9 x ^{4}}{16} + \frac{15 x ^{2} y ^{4}}{4} + \frac{100 y ^{8}}{16}

Streiche

\frac{100 y ^{8}}{16} : \frac{25 y ^{8}}{4}

= \frac{9 x ^{4}}{16} + \frac{15 x ^{2} y ^{4}}{4} + \frac{25 y ^{8}}{4}

e x p an d (sin (2 θ) + 2 sin (θ)) (1 - cos (θ))

e x p an d x (x - 10 x)

e x p an d \frac{( sin ( x ) e ^{x} ) - ( e ^{x} \cdot cos ( x ) )}{( sin ( x ) ) ^{2}}

e x p an d \frac{( x + 2 ) ( x - 1 )}{x - 2}

e x p an d \frac{7 !}{2 ! 5 !}