展开 1/((x+1)ln(x+1))

解答

展开

\frac{1}{( x + 1 ) ln ( x + 1 )}

\frac{1}{x ln ( x + 1 ) + ln ( x + 1 )}

求解步骤

\frac{1}{( x + 1 ) ln ( x + 1 )}

乘开

(x + 1) ln (x + 1) : x ln (x + 1) + ln (x + 1)

= \frac{1}{x ln ( x + 1 ) + ln ( x + 1 )}

e x p an d \frac{- 3 s ^{2} + 9 s + 18}{( s ^{2} - 4 ) ( s - 3 ) ( s + 1 )}

s im pl i f y (4 x + \frac{1}{3}) (4 x - \frac{1}{3})

e x p an d + P (- 1, 8) y Q (5, - 6)

e x p an d 2 y (1 - 2 x^{2}) e^{- x^{2} - y^{2}}

e x p an d (8) (4) (- 4) (- 8) (- 12) (- 16)