erweitern E(x)(ax^1+b|x^2=x^2|)

Lösung

erweitern

E (x) (a x^{1} + b x^{2} = x^{2})

a x^{1} E (x) + b = x^{2} x^{2} E (x)

Schritte zur Lösung

E (x) (a x^{1} + b x^{2} = x^{2})

= E (x) (a x^{1} + b = x^{2} x^{2})

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = E (x), b = a x^{1}, c = b x^{2} = x^{2}

= E (x) a x^{1} + E (x) b x^{2} = x^{2}

= a x^{1} E (x) + b = x^{2} x^{2} E (x)

e x p an d \frac{( 2 ( n + 1 ) ) !}{2 ^{n + 1} ( n + 1 ) ! ( n + 1 )}

e x p an d \frac{- x ^{2} + 2 x + 3}{( x ^{2} + 3 ) ^{2}}

e x p an d \frac{20 ( 249 - 2 )}{49}

e x p an d (x^{3} - 4 x^{2} + x - 4) (x^{2} = 18 x + 82)

e x p an d \frac{( x ) ( 2 x + 1 )}{2}