展开 (f\circ g)(2x-1)(-x^2)

解答

展开

(f \circ g) (2 x - 1) (- x^{2})

- 2 \circ f g x^{3} + \circ f g x^{2}

求解步骤

(f \circ g) (2 x - 1) (- x^{2})

= (\circ f g) (2 x - 1) (- x^{2})

使用分配律:

a (b - c) = ab - a c

a = (f \circ g) (- x^{2}), b = 2 x, c = 1

= (f \circ g) (- x^{2}) \cdot 2 x - (f \circ g) (- x^{2}) \cdot 1

= 2 x (\circ f g) (- x^{2}) - 1 \cdot (\circ f g) (- x^{2})

化简

2 x (\circ f g) (- x^{2}) - 1 \cdot (\circ f g) (- x^{2}) : - 2 \circ f g x^{3} + \circ f g x^{2}

= - 2 \circ f g x^{3} + \circ f g x^{2}

e x p an d (a - 12 b) + (- b + 12 a) i

e x p an d - \frac{( 8 x t - w y ) ^{2}}{y ^{2} t ^{2}}

s im pl i f y (R + \frac{C L s}{L s ^{2} + C}) (L s^{2} + C)

e x p an d \frac{b ^{2} + b b ^{2} - 4}{2}

e x p an d - 1 + 7 \cdot \frac{( 5 m - 2 )}{5}