What is 1+9(x-1)<7+9(x+1)\land 7x-3<= 18 ?

The solution to 1+9(x-1)<7+9(x+1)\land 7x-3<= 18 is x<= 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1+9(x-1)<7+9(x+1)\land 7x-3<= 18

1 + 9 (x - 1) < 7 + 9 (x + 1) and 7 x - 3 \leq 18

x \leq 3

Interval Notation

(- \infty, 3]

Solution steps

1 + 9 (x - 1) < 7 + 9 (x + 1) and 7 x - 3 \leq 18

1 + 9 (x - 1) < 7 + 9 (x + 1) :

True for all

x

7 x - 3 \leq 18 : x \leq 3

Combine the intervals

True for all x and x \leq 3

Merge Overlapping Intervals

x \leq 3

\frac{7 i}{4 + i}

2 5^{\frac{4}{3}}

r^{2} + 10 r + 25 = 0

- (4)^{3}

(1 + \frac{0.01}{2})^{2} - 1

What is 1+9(x-1)<7+9(x+1)\land 7x-3<= 18 ?
The solution to 1+9(x-1)<7+9(x+1)\land 7x-3<= 18 is x<= 3