What are the solutions to the equation 6x^2-4x-5=4x ?

The solutions to the equation 6x^2-4x-5=4x are x=(4+sqrt(46))/6 ,x=(4-sqrt(46))/6

Find the zeros of 6x^2-4x-5=4x

The zeros of 6x^2-4x-5=4x are x=(4+sqrt(46))/6 ,x=(4-sqrt(46))/6

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6 x^{2} - 4 x - 5 = 4 x

x = \frac{4 + 46}{6}, x = \frac{4 - 46}{6}

Decimal Notation

x = 1.79705 \dots, x = - 0.46372 \dots

Solution steps

6 x^{2} - 4 x - 5 = 4 x

Move

4 x

to the left side

6 x^{2} - 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 8)^{2} - 4 \cdot 6 (- 5) = 246

x_{1, 2} = \frac{- ( - 8 ) \pm 2 46}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 46}{2 \cdot 6}, x_{2} = \frac{- ( - 8 ) - 2 46}{2 \cdot 6}

x = \frac{- ( - 8 ) + 2 46}{2 \cdot 6} : \frac{4 + 46}{6}

x = \frac{- ( - 8 ) - 2 46}{2 \cdot 6} : \frac{4 - 46}{6}

The solutions to the quadratic equation are:

x = \frac{4 + 46}{6}, x = \frac{4 - 46}{6}

\frac{- 6}{7}

m^{2} + 10 m + 24 = 0

s^{2} - 100 = 0

49 x^{4} - 64

\frac{12 !}{2 ! ( 12 - 2 ) !}

What are the solutions to the equation 6x^2-4x-5=4x ?
The solutions to the equation 6x^2-4x-5=4x are x=(4+sqrt(46))/6 ,x=(4-sqrt(46))/6
Find the zeros of 6x^2-4x-5=4x
The zeros of 6x^2-4x-5=4x are x=(4+sqrt(46))/6 ,x=(4-sqrt(46))/6