What are the solutions to the equation 4x^2-30x+45=0 ?

The solutions to the equation 4x^2-30x+45=0 are x=(3(5+sqrt(5)))/4 ,x=(3(5-sqrt(5)))/4

Find the zeros of 4x^2-30x+45=0

The zeros of 4x^2-30x+45=0 are x=(3(5+sqrt(5)))/4 ,x=(3(5-sqrt(5)))/4

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4 x^{2} - 30 x + 45 = 0

x = \frac{3 ( 5 + 5 )}{4}, x = \frac{3 ( 5 - 5 )}{4}

Decimal Notation

x = 5.42705 \dots, x = 2.07294 \dots

Solution steps

4 x^{2} - 30 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 4 \cdot 45}{2 \cdot 4}

(- 30)^{2} - 4 \cdot 4 \cdot 45 = 65

x_{1, 2} = \frac{- ( - 30 ) \pm 6 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 6 5}{2 \cdot 4}, x_{2} = \frac{- ( - 30 ) - 6 5}{2 \cdot 4}

x = \frac{- ( - 30 ) + 6 5}{2 \cdot 4} : \frac{3 ( 5 + 5 )}{4}

x = \frac{- ( - 30 ) - 6 5}{2 \cdot 4} : \frac{3 ( 5 - 5 )}{4}

The solutions to the quadratic equation are:

x = \frac{3 ( 5 + 5 )}{4}, x = \frac{3 ( 5 - 5 )}{4}

0 = 2 x^{2} - 2 x - 760

5 [- 7 x - 6 + 5 (x + 1)] = 7 x - 3

10 > 16 - 1.2 h

\frac{1}{4} + \frac{1}{10}

6 x^{2} + 78 x + 240 = 0

What are the solutions to the equation 4x^2-30x+45=0 ?
The solutions to the equation 4x^2-30x+45=0 are x=(3(5+sqrt(5)))/4 ,x=(3(5-sqrt(5)))/4
Find the zeros of 4x^2-30x+45=0
The zeros of 4x^2-30x+45=0 are x=(3(5+sqrt(5)))/4 ,x=(3(5-sqrt(5)))/4