2x^2+16x+14=0

解

2 x^{2} + 16 x + 14 = 0

x = - 1, x = - 7

解答ステップ

2 x^{2} + 16 x + 14 = 0

解くとthe二次式

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 \cdot 14 = 12

x_{1, 2} = \frac{- 16 \pm 12}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 16 + 12}{2 \cdot 2}, x_{2} = \frac{- 16 - 12}{2 \cdot 2}

x = \frac{- 16 + 12}{2 \cdot 2} : - 1

x = \frac{- 16 - 12}{2 \cdot 2} : - 7

二次equationの解:

x = - 1, x = - 7