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受欢迎的代数 >

solvefor y,f=x^{23}-10y+15xy^2

解答

求解

y, f = x^{23} - 10 y + 15 x y^{2}

解答

y = \frac{10 + 100 - 60 x ( x ^{23} - f )}{30 x}, y = \frac{10 - 100 - 60 x ( x ^{23} - f )}{30 x}; x \neq = 0

求解步骤

f = x^{23} - 10 y + 15 x y^{2}

交换两边

x^{23} - 10 y + 15 x y^{2} = f

将

f

para o lado esquerdo

x^{23} - 10 y + 15 x y^{2} - f = 0

改写成标准形式

a x^{2} + b x + c = 0

15 x y^{2} - 10 y + x^{23} - f = 0

使用求根公式求解

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 15 x ( x ^{23} - f )}{2 \cdot 15 x}

化简

(- 10)^{2} - 4 \cdot 15 x (x^{23} - f) : 100 - 60 x (x^{23} - f)

y_{1, 2} = \frac{- ( - 10 ) \pm 100 - 60 x ( x ^{23} - f )}{2 \cdot 15 x}; x \neq = 0

将解分隔开

y_{1} = \frac{- ( - 10 ) + 100 - 60 x ( x ^{23} - f )}{2 \cdot 15 x}, y_{2} = \frac{- ( - 10 ) - 100 - 60 x ( x ^{23} - f )}{2 \cdot 15 x}

y = \frac{- ( - 10 ) + 100 - 60 x ( x ^{23} - f )}{2 \cdot 15 x} : \frac{10 + 100 - 60 x ( x ^{23} - f )}{30 x}

y = \frac{- ( - 10 ) - 100 - 60 x ( x ^{23} - f )}{2 \cdot 15 x} : \frac{10 - 100 - 60 x ( x ^{23} - f )}{30 x}

二次方程组的解是:

y = \frac{10 + 100 - 60 x ( x ^{23} - f )}{30 x}, y = \frac{10 - 100 - 60 x ( x ^{23} - f )}{30 x}; x \neq = 0

作图

流行的例子

x^{2} - 19 = 0

x^{2} + 3 x + 28 = 0

y^{2} = 144

4 b^{2} - 5 b - 4 = 0

x (x - 6) = 16