What are the solutions to the equation 8x^2+9x=8 ?

The solutions to the equation 8x^2+9x=8 are x=(-9+sqrt(337))/(16),x=(-9-sqrt(337))/(16)

Find the zeros of 8x^2+9x=8

The zeros of 8x^2+9x=8 are x=(-9+sqrt(337))/(16),x=(-9-sqrt(337))/(16)

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8 x^{2} + 9 x = 8

x = \frac{- 9 + 337}{16}, x = \frac{- 9 - 337}{16}

Decimal Notation

x = 0.58484 \dots, x = - 1.70984 \dots

Solution steps

8 x^{2} + 9 x = 8

Move

8

to the left side

8 x^{2} + 9 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 8 ( - 8 )}{2 \cdot 8}

9^{2} - 4 \cdot 8 (- 8) = 337

x_{1, 2} = \frac{- 9 \pm 337}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 9 + 337}{2 \cdot 8}, x_{2} = \frac{- 9 - 337}{2 \cdot 8}

x = \frac{- 9 + 337}{2 \cdot 8} : \frac{- 9 + 337}{16}

x = \frac{- 9 - 337}{2 \cdot 8} : \frac{- 9 - 337}{16}

The solutions to the quadratic equation are:

x = \frac{- 9 + 337}{16}, x = \frac{- 9 - 337}{16}

\frac{x - 4}{x + 6} < 1

21 \leq 3 + 9 x

112

(1 + \frac{0.04}{2})^{2} - 1

\frac{23 + 6 ^{2}}{6}

What are the solutions to the equation 8x^2+9x=8 ?
The solutions to the equation 8x^2+9x=8 are x=(-9+sqrt(337))/(16),x=(-9-sqrt(337))/(16)
Find the zeros of 8x^2+9x=8
The zeros of 8x^2+9x=8 are x=(-9+sqrt(337))/(16),x=(-9-sqrt(337))/(16)