zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor p,p^1(v^1)/(t^1)=p^2(v^2)/(t^2)

解答

求解

p, p^{1} \frac{v ^{1}}{t ^{1}} = p^{2} \frac{v ^{2}}{t ^{2}}

解答

p = \frac{t}{v}, p = 0; \frac{v ^{2}}{t ^{2}} \neq = 0

求解步骤

p^{1} \frac{v ^{1}}{t ^{1}} = p^{2} \frac{v ^{2}}{t ^{2}}

展开

p^{1} \frac{v ^{1}}{t ^{1}} : \frac{p v}{t}

展开

p^{2} \frac{v ^{2}}{t ^{2}} : \frac{p ^{2} v ^{2}}{t ^{2}}

\frac{p v}{t} = \frac{p ^{2} v ^{2}}{t ^{2}}

交换两边

\frac{p ^{2} v ^{2}}{t ^{2}} = \frac{p v}{t}

将

\frac{p v}{t}

para o lado esquerdo

\frac{p ^{2} v ^{2}}{t ^{2}} - \frac{p v}{t} = 0

改写成标准形式

a x^{2} + b x + c = 0

\frac{v ^{2} p ^{2}}{t ^{2}} - \frac{v p}{t} = 0

使用求根公式求解

p_{1, 2} = \frac{- ( - \frac{v}{t} ) \pm ( - \frac{v}{t} ) ^{2} - 4 \cdot \frac{v ^{2}}{t ^{2}} \cdot 0}{2 \cdot \frac{v ^{2}}{t ^{2}}}

化简

(- \frac{v}{t})^{2} - 4 \cdot \frac{v ^{2}}{t ^{2}} \cdot 0 : \frac{v}{t}

p_{1, 2} = \frac{- ( - \frac{v}{t} ) \pm \frac{v}{t}}{2 \cdot \frac{v ^{2}}{t ^{2}}}; \frac{v ^{2}}{t ^{2}} \neq = 0

将解分隔开

p_{1} = \frac{- ( - \frac{v}{t} ) + \frac{v}{t}}{2 \cdot \frac{v ^{2}}{t ^{2}}}, p_{2} = \frac{- ( - \frac{v}{t} ) - \frac{v}{t}}{2 \cdot \frac{v ^{2}}{t ^{2}}}

p = \frac{- ( - \frac{v}{t} ) + \frac{v}{t}}{2 \frac{v ^{2}}{t ^{2}}} : \frac{t}{v}

p = \frac{- ( - \frac{v}{t} ) - \frac{v}{t}}{2 \frac{v ^{2}}{t ^{2}}} : 0

二次方程组的解是:

p = \frac{t}{v}, p = 0; \frac{v ^{2}}{t ^{2}} \neq = 0

作图

流行的例子

(x + 1) - x (x - 3) = 6

x^{2} + 20 x + 99 = 0

3 x^{2} = 8 x

completesquare x^2-2x-5=0

co m pl e t es q u a re x^{2} - 2 x - 5 = 0

2 y^{2} - y = 0