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受欢迎的代数 >

solvefor a,5a^2+5b^2=2a-6b-2

解答

求解

a, 5 a^{2} + 5 b^{2} = 2 a - 6 b - 2

解答

a = \frac{1 + - 25 b ^{2} - 30 b - 9}{5}, a = \frac{1 - - 25 b ^{2} - 30 b - 9}{5}

求解步骤

5 a^{2} + 5 b^{2} = 2 a - 6 b - 2

将

2

para o lado esquerdo

5 a^{2} + 5 b^{2} + 2 = 2 a - 6 b

将

6 b

para o lado esquerdo

5 a^{2} + 5 b^{2} + 2 + 6 b = 2 a

将

2 a

para o lado esquerdo

5 a^{2} + 5 b^{2} + 2 + 6 b - 2 a = 0

改写成标准形式

a x^{2} + b x + c = 0

5 a^{2} - 2 a + 5 b^{2} + 2 + 6 b = 0

使用求根公式求解

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( 5 b ^{2} + 2 + 6 b )}{2 \cdot 5}

化简

(- 2)^{2} - 4 \cdot 5 (5 b^{2} + 2 + 6 b) : 2 - 25 b^{2} - 30 b - 9

a_{1, 2} = \frac{- ( - 2 ) \pm 2 - 25 b ^{2} - 30 b - 9}{2 \cdot 5}

将解分隔开

a_{1} = \frac{- ( - 2 ) + 2 - 25 b ^{2} - 30 b - 9}{2 \cdot 5}, a_{2} = \frac{- ( - 2 ) - 2 - 25 b ^{2} - 30 b - 9}{2 \cdot 5}

a = \frac{- ( - 2 ) + 2 - 25 b ^{2} - 30 b - 9}{2 \cdot 5} : \frac{1 + - 25 b ^{2} - 30 b - 9}{5}

a = \frac{- ( - 2 ) - 2 - 25 b ^{2} - 30 b - 9}{2 \cdot 5} : \frac{1 - - 25 b ^{2} - 30 b - 9}{5}

二次方程组的解是:

a = \frac{1 + - 25 b ^{2} - 30 b - 9}{5}, a = \frac{1 - - 25 b ^{2} - 30 b - 9}{5}

作图

流行的例子

4 x^{2} - 6 x + 4 = 0

- \frac{1}{2} x^{2} - 24 = 0

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