39y^2-148y+132=0

解

39 y^{2} - 148 y + 132 = 0

y = \frac{2 ( 37 + 82 )}{39}, y = \frac{2 ( 37 - 82 )}{39}

十進法表記

y = 2.36181 \dots, y = 1.43305 \dots

解答ステップ

39 y^{2} - 148 y + 132 = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 148 ) \pm ( - 148 ) ^{2} - 4 \cdot 39 \cdot 132}{2 \cdot 39}

(- 148)^{2} - 4 \cdot 39 \cdot 132 = 482

y_{1, 2} = \frac{- ( - 148 ) \pm 4 82}{2 \cdot 39}

解を分離する

y_{1} = \frac{- ( - 148 ) + 4 82}{2 \cdot 39}, y_{2} = \frac{- ( - 148 ) - 4 82}{2 \cdot 39}

y = \frac{- ( - 148 ) + 4 82}{2 \cdot 39} : \frac{2 ( 37 + 82 )}{39}

y = \frac{- ( - 148 ) - 4 82}{2 \cdot 39} : \frac{2 ( 37 - 82 )}{39}

二次equationの解:

y = \frac{2 ( 37 + 82 )}{39}, y = \frac{2 ( 37 - 82 )}{39}