log_{0.2}(5x-6)>log_{0.2}(x^2)

解答

lo g_{0.2} (5 x - 6) > lo g_{0.2} (x^{2})

\frac{6}{5} < x < 2 or x > 3

间隔符号

(\frac{6}{5}, 2) \cup (3, \infty)

十进制

1.2 < x < 2 or x > 3

求解步骤

lo g_{0.2} (5 x - 6) > lo g_{0.2} (x^{2})

使用对数运算法则

5 x - 6 < x^{2} and 5 x - 6 > 0

5 x - 6 < x^{2} and 5 x - 6 > 0 : \frac{6}{5} < x < 2 or x > 3

\frac{6}{5} < x < 2 or x > 3

(x + 4) (x - 1) (5 + x) > 0

s im pl i f y \frac{9}{2}

- 2 + 3 ∣ 4 x - 3 ∣ = 16

500 = N_{0} (1.25)^{1.25}

s im pl i f y \frac{2 ^{2}}{3 ^{2}}