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受欢迎的代数 >

solvefor t,s=-16t^2+64t

解答

求解

t, s = - 16 t^{2} + 64 t

解答

t = - \frac{- 8 + - s + 64}{4}, t = \frac{- s + 64 + 8}{4}

求解步骤

s = - 16 t^{2} + 64 t

交换两边

- 16 t^{2} + 64 t = s

将

s

para o lado esquerdo

- 16 t^{2} + 64 t - s = 0

使用求根公式求解

t_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) ( - s )}{2 ( - 16 )}

化简

6 4^{2} - 4 (- 16) (- s) : 8 64 - s

t_{1, 2} = \frac{- 64 \pm 8 64 - s}{2 ( - 16 )}

将解分隔开

t_{1} = \frac{- 64 + 8 64 - s}{2 ( - 16 )}, t_{2} = \frac{- 64 - 8 64 - s}{2 ( - 16 )}

t = \frac{- 64 + 8 64 - s}{2 ( - 16 )} : - \frac{- 8 + - s + 64}{4}

t = \frac{- 64 - 8 64 - s}{2 ( - 16 )} : \frac{- s + 64 + 8}{4}

二次方程组的解是:

t = - \frac{- 8 + - s + 64}{4}, t = \frac{- s + 64 + 8}{4}

作图

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