What are the solutions to the equation (5x+7)^2=3 ?

The solutions to the equation (5x+7)^2=3 are x=(sqrt(3)-7)/5 ,x=(-sqrt(3)-7)/5

Find the zeros of (5x+7)^2=3

The zeros of (5x+7)^2=3 are x=(sqrt(3)-7)/5 ,x=(-sqrt(3)-7)/5

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(5 x + 7)^{2} = 3

x = \frac{3 - 7}{5}, x = \frac{- 3 - 7}{5}

Decimal Notation

x = - 1.05358 \dots, x = - 1.74641 \dots

Solution steps

(5 x + 7)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 7 = 3 : x = \frac{3 - 7}{5}

Solve

5 x + 7 = - 3 : x = \frac{- 3 - 7}{5}

The solutions to the quadratic equation are:

x = \frac{3 - 7}{5}, x = \frac{- 3 - 7}{5}

- 4 (v + 4) = 3 (v + 4) + 7

36 + 64

x^{2} = \frac{144}{169}

x^{3} + 3 x^{2} + 3 x + 9

2 x = 300

What are the solutions to the equation (5x+7)^2=3 ?
The solutions to the equation (5x+7)^2=3 are x=(sqrt(3)-7)/5 ,x=(-sqrt(3)-7)/5
Find the zeros of (5x+7)^2=3
The zeros of (5x+7)^2=3 are x=(sqrt(3)-7)/5 ,x=(-sqrt(3)-7)/5